How to code diamond pattern in C#?
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Diamond patterns are a common exercise for beginners learning to code in C#. They involve creating a pattern of asterisks (*) in the shape of a diamond. While they may seem simple, they can actually be quite challenging to create. In this blog, we will go over the steps to create a diamond pattern in C#.
The first step in creating a diamond pattern is to determine the size of the pattern. The size of the pattern will determine how many rows and columns of asterisks are needed to create the diamond shape. The size of the pattern can be determined by the user or it can be hardcoded into the program.
Once the size of the pattern has been determined, the next step is to create a loop that will iterate through each row of the pattern. The loop should start at the top of the pattern and work its way down to the middle. In each iteration, the loop should determine how many asterisks are needed for that row. This can be done by using a formula that takes into account the size of the pattern and the current row number.
After the top half of the pattern has been created, the loop should then continue through the middle row and then the bottom half of the pattern. For the middle row, the number of asterisks needed will be equal to the size of the pattern. For the bottom half of the pattern, the loop should again use a formula to determine the number of asterisks needed for each row.
Once the loop has completed its iterations, the diamond pattern will be complete. Here is an example of what the code might look like in C#:
int i, j, count = 1, number=5;
count = number - 1;
for (j = 1; j <= number; j++)
{
for (i = 1; i <= count; i++)
Console.Write(" ");
count--;
for (i = 1; i <= 2 * j - 1; i++)
Console.Write("*");
Console.WriteLine();
}
count = 1;
for (j = 1; j <= number - 1; j++)
{
for (i = 1; i <= count; i++)
Console.Write(" ");
count++;
for (i = 1; i <= 2 * (number - j) - 1; i++)
Console.Write("*");
Console.WriteLine();
}
This code will create a diamond pattern with a size of 9. The output will be:
*
***
*****
*******
*********
*******
*****
***
*
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